Re: Using functions as filters in queries
От | Stephan Szabo |
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Тема | Re: Using functions as filters in queries |
Дата | |
Msg-id | 20030312140421.O56401-100000@megazone23.bigpanda.com обсуждение исходный текст |
Ответ на | Re: Using functions as filters in queries (Stephan Szabo <sszabo@megazone23.bigpanda.com>) |
Ответы |
Re: Using functions as filters in queries
Re: Using functions as filters in queries |
Список | pgsql-admin |
On Wed, 12 Mar 2003, Stephan Szabo wrote: > > On Mon, 10 Mar 2003, Chris Mungall wrote: > > > I have a problem that can be reduced to this equivalent but simpler > > problem: > > > EXPLAIN ANALYZE select * from t where n=5 AND x like 'a%'; > > 5 is a constant. > > > Case 2: > > > > Now I want to replace the "n=5" clause with a function: > > > > CREATE FUNCTION f(t, int) RETURNS bool AS > > 'SELECT $1.n = $2' > > LANGUAGE 'sql'; > > > > EXPLAIN ANALYZE select * from t where f(t, 5) AND x like 'a%'; > > > > Now looking at the two cases (without and with function) I can see that > > they are equivalent, but Pg treats them differently. I guess it is failing > > to distiguish between two cases - if the function has no FROM clause, then > > it is a simple case of variable substitution into the original WHERE > > clause. If it does include a FROM clause, it's not so simple and > > optimisation is hard, so the function becomes the filter. > > It doesn't look at the contents of the function. It looks at whether the > function is defined IMMUTABLE, STABLE or VOLATILE. With a VOLATILE > function (the default), the system is not guaranteed that given the > same arguments that the result is the same. You might want to read > the description in the manpage for CREATE FUNCTION. Of course, I misread what explain did (without trying the enable_seqscan=off case) and this is still not indexable because even after that, you'll not get a clause on the outside that it considers indexable. It is smart enough (7.4 anyway) to make the filter ((t.*).n)=5 which I thought it'd index, but doesn't. :(
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