Hi,
PLease look at the query.The syntax is
"SELECT attribute_name[,attr2,..] FROM tables WHERE attribute =[LIKE,IN,..] ETC..
It looks in ur query that province is an attribute as well as a query.
Reagrds
Sharmad
On Wed, 22 Jan 2003 14:18:32 +0800
ryanne cruz <ryanne.cruz@up.edu.ph> wrote:
>
> hi list.
>
> this is my script:
>
> $query7="select provinceid from province where province like '$tablename1';";
> $result7=pg_exec($conn,$query7);
> if(!$result7){
> .
> .
> .}
> else {
> .
> .
> .
> }
>
> my problem is when the value of the variable $tablename1 is not on the table
> province, it doesn't go to the if statements. what am i doing wrong?
>
> thanks!
>
>
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