Re: To use a VIEW or not to use a View.....
От | Stephan Szabo |
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Тема | Re: To use a VIEW or not to use a View..... |
Дата | |
Msg-id | 20030122130604.C1159-100000@megazone23.bigpanda.com обсуждение исходный текст |
Ответ на | Re: To use a VIEW or not to use a View..... (Tomasz Myrta <jasiek@klaster.net>) |
Ответы |
Re: To use a VIEW or not to use a View.....
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Список | pgsql-sql |
On Wed, 22 Jan 2003, Tomasz Myrta wrote: > Let's make some test: > > First, let's create some simple view with 2 tables join: > drop view pm; > create view pm as > select > id_przystanku, > m.nazwa > from > przystanki p > join miasta m using (id_miasta); > > explain select * from pm where id_przystanku=1230; > Nested Loop (cost=0.00..6.26 rows=1 width=23) > -> Index Scan using przystanki_pkey on przystanki p (cost=0.00..3.14 rows=1 width=8) > -> Index Scan using miasta_pkey on miasta m (cost=0.00..3.10 rows=1 width=15) > > > Next, let's try query using this view 2 times with explicit join: > explain select * from pm a join pm b using(id_przystanku) where id_przystanku=1230; > Hash Join (cost=13.00..30.10 rows=1 width=46) > -> Hash Join (cost=6.74..21.02 rows=374 width=23) > -> Seq Scan on przystanki p (cost=0.00..7.74 rows=374 width=8) > -> Hash (cost=5.99..5.99 rows=299 width=15) > -> Seq Scan on miasta m (cost=0.00..5.99 rows=299 width=15) > -> Hash (cost=6.26..6.26 rows=1 width=23) > -> Nested Loop (cost=0.00..6.26 rows=1 width=23) > -> Index Scan using przystanki_pkey on przystanki p (cost=0.00..3.14 rows=1 width=8) > -> Index Scan using miasta_pkey on miasta m (cost=0.00..3.10 rows=1 width=15) > > And now similiar view, but without nesting views: > drop view pm2; > create view pm2 as > select > id_przystanku, > m1.nazwa as nazwa1, > m2.nazwa as nazwa2 > from > przystanki p1 > join miasta m1 using (id_miasta) > join przystanki p2 using (id_przystanku) > join miasta m2 on (m2.id_miasta=p2.id_miasta); That's not the same join for optimization purposes since postgresql treats explicit join syntax as a constraint on the ordering of joins. The same join would be something like: przystanki p1 join miasta m1 using (id_miasta) join (przystanki p2 join miasta m2 using (id_miasta))using (id_przystanku) minus the fact I think you'd need some explicit naming in there.
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