Re: extract and variables in PL/pgSQL
От | Jan Wieck |
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Тема | Re: extract and variables in PL/pgSQL |
Дата | |
Msg-id | 200206061220.g56CKtO26245@saturn.janwieck.net обсуждение исходный текст |
Ответ на | extract and variables in PL/pgSQL (Roberto Mello <rmello@cc.usu.edu>) |
Ответы |
Re: extract and variables in PL/pgSQL
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Список | pgsql-sql |
Roberto Mello wrote: > Hi, > > Someone in another list asked about this function. I'm not sure why it > doesn't work. What am I missing? > > CREATE FUNCTION zastras(timestamp) RETURNS integer AS ' > declare > w_temp1 alias for $1; > w_result integer; > begin > SELECT INTO w_result EXTRACT(epoch from timestamp w_temp1); > return w_result; > > end; > ' language 'plpgsql'; > > NOTICE: Error occurred while executing PL/pgSQL function zastras > NOTICE: line 5 at select into variables First you're missing the error message, which should read something like ERROR: parser: parse error at or near "$1" Doesn't help much here, but it is usually a good idea to include error messages in reports like this. I'm not 100% sure, but it seems that the PostgreSQL main parser doesn't support parameters in the place of this "timestamp" expression construct. It works if you leave out the keyword "timestamp" writing SELECT INTO w_result EXTRACT(epoch from w_temp1); because the variable w_temp1 is known to be of type timestamp already and therefore the a_expr node on the right hand side of from is valid. Jan -- #======================================================================# # It's easier to get forgiveness for being wrong than for being right. # # Let's break this rule - forgive me. # #================================================== JanWieck@Yahoo.com #
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