Re: Getting matching and non-matching results (long)
От | Stephan Szabo |
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Тема | Re: Getting matching and non-matching results (long) |
Дата | |
Msg-id | 20011205130527.W17641-100000@megazone23.bigpanda.com обсуждение исходный текст |
Ответ на | Getting matching and non-matching results (long) (Roberto Mello <rmello@cc.usu.edu>) |
Ответы |
Re: Getting matching and non-matching results (long)
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Список | pgsql-sql |
> create table sds_grades ( > grade_id integer > constraint sds_grades_pk primary key, > grade_name varchar(100) > ); > > create table sds_offenders ( > offender_id integer > constraint sds_offenders_pk primary key, > participant_id integer > constraint sds_offenders_part_id_fk references sds_participants, > incident_id integer > constraint sds_offenders_incident_id_fk references sds_incidents on delete cascade, > unknown_count integer, > grade_id integer > constraint sds_offenders_grade_id_fk references sds_grades, > ... > ); > > SELECT COUNT(incident_id), drug_name, grade_name > FROM sds_offenders o, sds_drugs d, sds_drug_offenses do, sds_grades g > WHERE o.drug_p = 't' > AND o.offender_id = do.offender_id > AND d.drug_id = do.drug_id > GROUP BY drug_name, grade_name, d.sort_key > ORDER BY d.sort_key I think you need a g.gradeid=o.gradeid in the where clause as well to constrain g to the grade for which the offender belonged, right?
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