Re: Fixing faulty dates - select on day part of a date field

Hi

1. You could use date_part(). Try these things
select date_part('day', now());select date_part('month', now());select date_part('year', now());

2. Yeah, should be able to do it in one update

Regards,
Patrik Kudo

On Thu, 29 Nov 2001, Gary Stainburn wrote:

> Hi all,
>
> I've got a problem with dates on one of my tables. I've been inserting dates
> in the format 'dd/mm/ccyy' which for the days 13-31 for each month worked
> fine.
>
> The problem I have is that for the days 01-12 for each month, the date was
> interpretted as 'mm/dd/ccyy'.  Now I know about it I need to fix it.
>
> Two questions.
>
> 1) how can I select on part of a date?  I need to select all records where
> the day is not > 12.
> 2) can I do this in a single update, i.e. can I do something around
>
> update calls set xdate =  ???? where ??????;
>
> --
> Gary Stainburn
>
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