Re: JDBC bug?
От | Ross J. Reedstrom |
---|---|
Тема | Re: JDBC bug? |
Дата | |
Msg-id | 20011126155447.B5801@rice.edu обсуждение исходный текст |
Ответ на | Re: JDBC bug? ("Colin Freas" <cef6@georgetown.edu>) |
Список | pgsql-jdbc |
On Mon, Nov 26, 2001 at 04:24:46PM -0500, Colin Freas wrote: > > Barry, > > I'm just saying that it's frustrating because in one of my earlier checks to > make sure my SQL was ok, I used Access 2000 with some linked tables to my Ah, here's the real problem: MS-Access 'helpfully' quotes all the identifiers for you, behind your back. Kind of like the 'helpful' things Word does as you type. I got bit by the same behavior: I created same tables from inside Access, and got to spend some time finding all the MiXedCase BuGs in PostgreSQL v 6.2 (or so). > Postgres db. When I ran 'select * from response where questionID=16' > through that, it worked without a hitch (actually, the 16 needed to be > '16'), so I figured the problem was somewhere else. Plus it was such simple > SQL, I mean, what could be wrong with it? I'd be the first to admit I > don't... well, I didn't... know the nuances of the SQL9X casing rules. My > issue, as stated in my initial note, was more that nobody (jdbc, postgres, > tomcat) told me that my where clause was, essentially, bogus. I mean, what > am I catching that SQLException for? > > And Bruce wrote... > >rs = stmt.executeQuery("select * from response where \"questionID\"=16"); > > That works. Indeed. BTW, as long as you stay away from software that meses with your queries, you can get away with writing: select * from response where questionID=16; As long as the table was created the same way (i.e., no quotes): create table response (questionID int , ...) The only problem is that the column name returned by the system will be questionid. Ross
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