Re: The ignored "_" character
От | Karel Zak |
---|---|
Тема | Re: The ignored "_" character |
Дата | |
Msg-id | 20010507101253.A194@ara.zf.jcu.cz обсуждение исходный текст |
Ответ на | The ignored "_" character (pgsql-bugs@postgresql.org) |
Список | pgsql-bugs |
On Mon, May 07, 2001 at 03:01:28AM -0400, pgsql-bugs@postgresql.org wrote: > Laszlo Kohl (lkohl@matavnet.hu) reports a bug with a severity of 2 > The lower the number the more severe it is. > > Short Description > The ignored "_" character > > Long Description > Hi, > > I am Laszlo from Hungary. > I have some problem with PostgreSQL. > > Environment: > PostgreSQL version: 7.0.3 > Server OS: RedHat 5.2 , Linux-Mandrake 7.2 > Client OS: RedHat 5.2 , Windows NT (pgAdmin) , Linux-Mandrake 7.2 > > The problem: > I create some users in database and then want to list them. > The "_" character is ignored in query statement. > The query: "select usename from pg_user where usename Like '%_u%' ;" > produces the same result as the query: > "select usename from pg_user where usename Like '%u%' ;" Sure it's not bug, please read something about the 'like' operator first, en example: http://postgresql.wavefire.com/users-lounge/docs/7.1/user/functions-matching.html If pattern does not contain percent signs or underscore, then the pattern only represents the string itself; in that case LIKE acts like the equals operator. An underscore (_) in pattern stands for (matches) any single character; a percent sign (%) matches any string of zero or more characters. You must run: ... usename LIKE '%\\_u%' Note two '\' must be used here because PostgreSQL parser first remove and 'like' operator obtain second only. Karel
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