Re: pattern matching operator
От | mig@utdt.edu |
---|---|
Тема | Re: pattern matching operator |
Дата | |
Msg-id | 200005161554.MAA20944@ant.utdt обсуждение исходный текст |
Ответ на | Re: pattern matching operator ("omid omoomi" <oomoomi@hotmail.com>) |
Список | pgsql-sql |
You can also do it in plain SQL, no regexp: select field,field from table where field like '%string%'; >X-Originating-IP: [195.200.226.110] >From: "omid omoomi" <oomoomi@hotmail.com> >Date: Tue, 16 May 2000 08:28:29 PDT >Content-Type: text/plain; format=flowed >X-Mailing-List: pgsql-sql@postgresql.org >Precedence: bulk >Sender: pgsql-sql-owner@hub.org > >Hi, >May be you need some thing like this: > >Select field1, field2 from table where field1~*'string' ; > >Hope that helps, >Omid Omoomi > > >>From: "Wallingford, Ted" <twallingford@indexc.com> >>To: pgsql-sql@postgresql.org >>Subject: [SQL] pattern matching operator >>Date: Tue, 16 May 2000 09:45:55 -0400 >> >>I need some help (the postgresql.org documentation pages are down??) >> >>I need to know what the pattern-matching operator is for string values in a >>select query... >> >>select field,field from table where field ?????? 'string'; >> >>I want to wildcard both ends of the string.. >> >>Thanks! >> >>Ted Wallingford > >________________________________________________________________________ >Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com >
В списке pgsql-sql по дате отправления: