Re: [SQL] Ordering a date_part() query ...

You may need to use CASE to output a column to be sorted on.


> 
> I have a query that looks like:
> 
> SELECT ( date_part('month', stat_period) || '/' || 
>          date_part('day', stat_period)   || '/' ||
>          date_part('year', stat_period)  || ' ' ||
>          date_part('hour', stat_period)  || ':00:00' ) as "Summary - by
> Day/Hour",
>        sum(impressions) as impressions, sum(click_thru) as click_thru
>   FROM banner_count
> GROUP BY "Summary - by Day/Hour";
> 
> 
> Works great, except that the output looks like:
> 
> Summary - by Day/Hour|impressions|click_thru
> ---------------------+-----------+----------
> 1/17/2000 23:00:00   |         63|         1
> 1/18/2000 0:00:00    |        151|         0
> 1/18/2000 10:00:00   |        348|         4
> 1/18/2000 11:00:00   |        804|         1
> 1/18/2000 12:00:00   |        180|         1
> 1/18/2000 1:00:00    |         89|         0
> 1/18/2000 2:00:00    |        112|         0
> 1/18/2000 3:00:00    |        178|         0
> 1/18/2000 4:00:00    |        184|         0
> 1/18/2000 5:00:00    |        133|         0
> 1/18/2000 6:00:00    |        119|         0
> 1/18/2000 7:00:00    |        148|         0
> 1/18/2000 8:00:00    |        224|         0
> 1/18/2000 9:00:00    |        272|         0
> 
> Notice the 10/11/12/etc hour stats come before the 1am stats?
> 
> So its sorting okay on the date, but I need to get it to d it on the time
> as well..
> 
> I'm still playing with it, but if someone can suggest a means of doing
> this, I'm all ears :)
> 
> Thanks...
> 
> Marc G. Fournier                   ICQ#7615664               IRC Nick: Scrappy
> Systems Administrator @ hub.org 
> primary: scrappy@hub.org           secondary: scrappy@{freebsd|postgresql}.org 
> 
> 
> ************
> 
> 


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