Re: Postgres: pg_hba.conf, md5, pg_shadow, encrypted passwords
От | Eliot Simcoe |
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Тема | Re: Postgres: pg_hba.conf, md5, pg_shadow, encrypted passwords |
Дата | |
Msg-id | 1F34E57D-4E2F-410F-A8C9-16AD2844C1E1@mac.com обсуждение исходный текст |
Ответ на | Re: Postgres: pg_hba.conf, md5, pg_shadow, encrypted passwords (Stephen Frost <sfrost@snowman.net>) |
Ответы |
Re: Postgres: pg_hba.conf, md5, pg_shadow, encrypted passwords
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Список | pgsql-hackers |
On Apr 21, 2005, at 8:59 PM, Stephen Frost wrote: > * Paul Tillotson (pntil@shentel.net) wrote: > >> Maybe I misunderstood, but I thought that others were saying that, if >> someone gets the contents of pg_shadow, then >> >> - if you use only "password" in your pg_hba.conf, he has to break >> one of >> the hashes first in order to log in. >> - but if you use "md5" in your pg_hba.conf, then he doesn't have to >> break the hashes at all. >> > > (in order to authenticate to your Postgres installation as a given > user) > > >> Is this correct? >> > > Yes, this is correct. > > >> I guess I personally felt "betrayed" when I heard this since I >> (naively) >> > > Me too. :/ > > >> assumed that the point of hashing passwords was to make it so that >> someone who is able to read your database is prevented from >> logging in >> and corrupting the data, installing root-kits, etc. >> > > The hash in pg_shadow should only be visible to the database > superuser, > or someone who has access to the unix account postgres runs as. > > >> Now I see that the point of md5 authenticate is to address an >> entirely >> different problem, namely, having the cleartext password being >> captured >> on the wire. >> > > The intention of the 'md5' method in pg_hba.conf is to avoid having > the > password go over the network in the clear, yes. Unfortunately, this > pretty much requires that the database have something which is > password-equivilant stored on disk. Wouldn't it be possible for postgres to rehash the md5 checksum of the password before storing it in pg_shadow? This seems preferable if not optimal. Does anyone know why this is not being done? > > Thanks, > > Stephen > Thanks, Eliot Simcoe
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