Re: [SQL] How match percent sign in SELECT using LIKE?

I have added this to the TODO list.  It is a good idea.


> Bruce Momjian wrote:
> > That is also an excellent idea.  Just convert their escape to \ inside
> > the parser.  Of course, they still have to use \\ to get a \, as in any
> > string.  Great idea.
> 
> You can even make it fully compliant if you want. (There are of course
> backward compatibility problems. I'm not sure what the Postgres policy is
> on this.)
> 
> - If the escape character is backslash, do nothing.
> - Otherwise, turn all backslashes in the string to double backslashes.
> - If the escape character is not set, stop here.
> - Turn all occurences of the escape character into a backslash except
>   where the escape character is doubled, where it should be made into a
>   single occurence.
> (Optionally, if "\n" is just an 'n' character, you can handle double
> occurences of the escape character by turning the first one into a
> backslash.)
> 
> Probably the best bet for PostgreSQL programmers is to always code Like
> clauses with an ESCAPE '\' (or however its written).
> 
> I really wish they'd chosen a character other than underscore for the
> "match one" wildcard... Is there any standard practice for seperating words
> in table names?
> 
> -Z-
> 


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