Re: [HACKERS] Open 6.5 items
От | maillist@candle.pha.pa.us (Bruce Momjian) |
---|---|
Тема | Re: [HACKERS] Open 6.5 items |
Дата | |
Msg-id | 199905250334.XAA02534@candle.pha.pa.us обсуждение исходный текст |
Список | pgsql-hackers |
> I'm not sure why "00/0" rather than "0/0" but basically you don't have > to show more octets than necessary based on the netmask. For example, > a netmask of 32 bits requires all 4, 24 bits requires 3, 16 needs 2 > and 8 (and less) needs 1. Technically you don't even need 1 octet for > 0 bits I suppose but "/0" doesn't make much sense. Well, then it is a bug. It should show 00/0. > > This is all based on my understanding. RFC lawyers, please feel free to > correct me. > > > > > When creating a table with either type inet or type cidr as a primary,unique > > > > key, the "198.68.123.0/24" and "198.68.123.0/27" are considered equal > > > > > > I guess I'll take a stab at it. I just need to know which of the following > > > is true. > > > > > > 198.68.123.0/24 < 198.68.123.0/27 > > > 198.68.123.0/24 > 198.68.123.0/27 > > > > > > Also, is it possible that the current behaviour is what we want? It seems > > > to me that if you make a network a primary key, you probably want to prevent > > > overlap. What we have does that. > > > > Good question. If we decide the current behaviour is OK, that is fine > > with me. Someone know understand this just needs to say so. > > And if not, what is the answer to the above question. Don't know. -- Bruce Momjian | http://www.op.net/~candle maillist@candle.pha.pa.us | (610) 853-3000+ If your life is a hard drive, | 830 Blythe Avenue + Christ can be your backup. | Drexel Hill, Pennsylvania19026
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