General Bug Report: adding column to table w/ index causes column not to be seen
От | Unprivileged user |
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Тема | General Bug Report: adding column to table w/ index causes column not to be seen |
Дата | |
Msg-id | 199905171538.LAA87295@hub.org обсуждение исходный текст |
Ответы |
Re: [BUGS] General Bug Report: adding column to table w/ index causes
column not to be seen
|
Список | pgsql-bugs |
============================================================================ POSTGRESQL BUG REPORT TEMPLATE ============================================================================ Your name : Diab Jerius Your email address : djerius@cfa.harvard.edu Category : runtime: back-end Severity : serious Summary: adding column to table w/ index causes column not to be seen System Configuration -------------------- Operating System : Solaris 2.6 PostgreSQL version : 6.4.2 Compiler used : SunCC 4.2 Hardware: --------- SunOS fondue 5.6 Generic_105181-12 sun4m sparc SUNW,SPARCstation-20 Versions of other tools: ------------------------ flex 2.5.4 -------------------------------------------------------------------------- Problem Description: -------------------- It seems that if a column is created in a table with an existant index, and an attempt is made to use that index, the backend doesn't see the new column. -------------------------------------------------------------------------- Test Case: ---------- The following SQL illustrates the problem: ====================================== drop table snafu; create table snafu ( a1 text, a2 text ); insert into snafu values ( 'snark', 'fido' ); create index snafu_i1 on snafu using hash ( a1 ); alter table snafu add column a3 text; update snafu set a3 = 'snzay' where a1 = 'snark'; ========================================= This results in drop table snafu; DROP create table snafu ( a1 text, a2 text ); CREATE insert into snafu values ( 'snark', 'fido' ); INSERT 156996266 1 create index snafu_i1 on snafu using hash ( a1 ); CREATE alter table snafu add column a3 text; ADD update snafu set a3 = 'snzay' where a1 = 'snark'; ERROR: Relation snafu does not have attribute a3 Removing the "create index ..." line causes the problem to go away. -------------------------------------------------------------------------- Solution: --------- --------------------------------------------------------------------------
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