I have found a way to assign NAN to a variable, thanks to the library
source code. Is this better than the code I just posted? Looks pretty
platform-specific, and we may be better with my earlier code to just use
num, which I have committed to the CURRENT tree.
The strange thing is that isnan(0/0) generates a floating-pointer error
and stops the program, but this does not. Strange.
---------------------------------------------------------------------------#include <stdio.h>#include <math.h>main(){
double x; x = 3; if (isnan((x-x)/(x-x))) printf("nan\n"); else printf("not nan\n");}
-- Bruce Momjian | http://www.op.net/~candle maillist@candle.pha.pa.us | (610)
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