Re: [HACKERS] subquery syntax broken
От | Bruce Momjian |
---|---|
Тема | Re: [HACKERS] subquery syntax broken |
Дата | |
Msg-id | 199802030317.WAA19375@candle.pha.pa.us обсуждение исходный текст |
Ответ на | Re: [HACKERS] subquery syntax broken ("Vadim B. Mikheev" <vadim@sable.krasnoyarsk.su>) |
Список | pgsql-hackers |
I believe it has to do with the fact that '=' has right precedence. Thomas, can you comment. Maybe we need to %right 'Op' at that point so it doesn't shift too early? > > Bruce Momjian wrote: > > > > > vac=> select * from x where y = (select max(y) from x); > > > ERROR: parser: parse error at or near "select" > > > vac=> select * from x where y <> (select max(y) from x); > > > ERROR: parser: parse error at or near "select" > > > > Sorry I missed that most obvious option. Here is the patch. I will > > apply it today. > > It doesn't work for =, >, etc: > > vac=> select * from x where y = (select max(y) from x); > ERROR: parser: parse error at or near "select" > > but work for others: > > vac=> select * from x where y @ (select max(y) from x); > ERROR: There is no operator '@' for types 'int4' and 'int4' > You will either have to retype this query using an explicit cast, > or you will have to define the operator using CREATE OPERATOR > > Also: > > > + | a_expr Op '(' SubSelect ')' > > + { > > + SubLink *n = makeNode(SubLink); > > + n->lefthand = lcons($1, NULL); > > + n->oper = lcons($2,NIL); > > + n->useor = false; > > + n->subLinkType = ALL_SUBLINK; > ^^^^^^^^^^^ > should be EXPR_SUBLINK > > + n->subselect = $4; > > + $$ = (Node *)n; > > + } > > Vadim > -- Bruce Momjian maillist@candle.pha.pa.us
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