Re: Rank
| От | Martin Knipper |
|---|---|
| Тема | Re: Rank |
| Дата | |
| Msg-id | 16616.195.212.29.187.1083678141.squirrel@webmail.mk-os.de обсуждение исходный текст |
| Ответ на | Rank ("Muhyiddin A.M Hayat" <middink@indo.net.id>) |
| Список | pgsql-sql |
Hey,
Muhyiddin A.M Hayat sagte:
>
> Dear All,
>
> I Have below table
>
> id | site_name | point
> ----+-----------+-------
> 1 | Site A | 40
> 2 | Site B | 90
> 3 | Site D | 22
> 4 | Site X | 98
>
> Would like to calc that Rank for each site, and look like
>
>
>
> id | site_name | point | rank
> ----+-----------+-------+------
> 1 | Site A | 40 | 3
> 2 | Site B | 90 | 2
> 3 | Site D | 22 | 4
> 4 | Site X | 98 | 1
>
> What can I do to get result like that
create temporary sequence ranking;
select *,nextval('ranking') as rank from yourTable order by site_name asc;
Greetins,
Martin Knipper
--
Martin Knipper
knipper@mk-os.de
http://www.mk-os.de
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