Re: sum() over (partition by order) question
От | Pavel Stehule |
---|---|
Тема | Re: sum() over (partition by order) question |
Дата | |
Msg-id | 162867790812311419n56e6d0f1qda590db5838d267a@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: sum() over (partition by order) question (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-hackers |
2008/12/31 Tom Lane <tgl@sss.pgh.pa.us>: > "Pavel Stehule" <pavel.stehule@gmail.com> writes: >> so I have to modify query to get expected values >> postgres=# select a, b, last_value(a) over (partition by b), >> last_value(a) over (partition by b order by a RANGE BETWEEN UNBOUNDED >> PRECEDING AND UNBOUNDED FOLLOWING) from foo; > >> it should be noticed in doc? > > It is --- see the comments at the bottom of > > http://developer.postgresql.org/pgdocs/postgres/functions-window.html > > regards, tom lane > there is maybe bug. It works well with explicit definition, but it not works when I will window good postgres=# select a, b, sum(a) over (partition by b order by a ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) from foo;a | b | sum ----+---+----- 1 | 1 | 19 1 | 1 | 19 2 | 1 | 19 2 | 1 | 19 4 | 1 | 19 4 | 1 | 19 5 | 1 | 1911 | 3 | 9312 | 3 | 9316| 3 | 9316 | 3 | 9316 | 3 | 9322 | 3 | 93 (13 rows) wrong postgres=# select a, b, sum(a) over (w) from foo window w as (partition by b order by a ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING);a | b | sum ----+---+----- 1 | 1 | 2 1 | 1 | 2 2 | 1 | 6 2 | 1 | 6 4 | 1 | 14 4 | 1 | 14 5 | 1 | 1911 | 3 | 1112 | 3 | 2316| 3 | 7116 | 3 | 7116 | 3 | 7122 | 3 | 93 (13 rows) regards Pavel Stehule
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