Re: Function with default value not replacing old definition of the function
От | Pavel Stehule |
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Тема | Re: Function with default value not replacing old definition of the function |
Дата | |
Msg-id | 162867790812102310j4cb7a0e5ycea09704fcdcac9b@mail.gmail.com обсуждение исходный текст |
Ответ на | Function with default value not replacing old definition of the function ("Rushabh Lathia" <rushabh.lathia@gmail.com>) |
Ответы |
Re: Function with default value not replacing old definition of the function
Re: Function with default value not replacing old definition of the function |
Список | pgsql-hackers |
Hello 2008/12/11 Rushabh Lathia <rushabh.lathia@gmail.com>: > Hi, > > Testcase: (8.4 CVS head) > ==================== > > CREATE OR REPLACE FUNCTION myfunc(y int) > RETURNS INTEGER AS $$ > select 100; > $$ language sql; > > CREATE OR REPLACE FUNCTION myfunc(y int, x integer DEFAULT 100) > RETURNS INTEGER AS $$ > select 200; > $$ language sql; > > select myfunc(10); > > myfunc > ---------- > 100 > (1 row) no, it's little bit different Default is only stored parameter value. You created two functions with two different signatures myfunc(int) myfunc(int, int) when you created function, we cannot check defaults, because we don't know if anybody use default or not. And when you call function, then postgres prefer function with most similar function. regards Pavel Stehule > > When create the same function again by added one default value, while > calling the function old function getting called. > > It seems that, function with defval not making any sense, if we want to call > the new function then we need to pass defval as well. > > select myfunc(10,10); > > myfunc > ---------- > 200 > (1 row) > > I think second function should replace the old definition of the function, > inputs ? > > > Thanks, > Rushabh Lathia > www.EnterpriseDB.com >
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