Re: Substring result short by 1
От | Tom Lane |
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Тема | Re: Substring result short by 1 |
Дата | |
Msg-id | 15048.1093985358@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Substring result short by 1 (David Filion <david@filiontech.com>) |
Список | pgsql-general |
David Filion <david@filiontech.com> writes: > prepaid=# select substring('15148300', 0, 5); > substring > ----------- > 1514 > (1 row) > I get a result with only the first 4 characters, not five. Why is > that? AFAICS this is per spec. It's a bit odd that SQL doesn't consider start position less than 1 as an error, but that's how the spec is written: a) Let C be the value of the <character value expression>, let LC be the length of C, and let S be the value of the <start position>. [ so for your example, LC = 8, S = 0 ] b) If <string length> is specified, then let L be the value of <string length> and let E be S+L. Otherwise, let E be the larger of LC + 1 and S. [ L = 5, E = S+L = 5 ] c) If either C, S, or L is the null value, then the result of the <character substring function> is the null value. [ nope ] d) If E is less than S, then an exception condition is raised: data exception-substring error. [ nope ] e) Case: i) If S is greater than LC or if E is less than 1, then the result of the <character substring function> is a zero- length string. [ nope ] ii) Otherwise, 1) Let S1 be the larger of S and 1. Let E1 be the smaller of E and LC+1. Let L1 be E1-S1. [ S1 = 1, E1 = 5, L1 = 4 ] 2) The result of the <character substring function> is a character string containing the L1 characters of C starting at character number S1 in the same order that the characters appear in C. [ result = what you got ] The only case in which you can get an error is by specifying a negative L. Otherwise, you get whatever part of the string overlaps your subscript range specification --- at either end. regards, tom lane
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