Re: --enable-debug does not work with gcc
От | Tom Lane |
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Тема | Re: --enable-debug does not work with gcc |
Дата | |
Msg-id | 15034.1170429785@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: --enable-debug does not work with gcc (NikhilS <nikkhils@gmail.com>) |
Ответы |
Re: --enable-debug does not work with gcc
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Список | pgsql-hackers |
NikhilS <nikkhils@gmail.com> writes: > True, this is how I myself circumvent this problem too. But IMHO, > explicitly passing CFLAGS when we are invoking --enable-debug (which does > add -g, but leaves some optimization flag around which deters debugging) > does not seem correct? If we did what you suggest, then --enable-debug would cause performance degradation, which would cause people to not use it, which would result in most binaries being completely undebuggable rather than only partially. Doesn't sound like a good tradeoff to me. Personally, in my development tree I use a Makefile.custom containing # back off optimization unless profiling ifeq ($(PROFILE),) CFLAGS:= $(patsubst -O2,-O1,$(CFLAGS)) endif -O1 still generates "uninitialized variable" warnings but the code is a lot saner to step through ... not perfect, but saner. It's been a workable compromise for a long time. I don't recommend developing with -O0, exactly because it disables some mighty valuable warnings. regards, tom lane
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