Re: BUG #17150: Unexpected outputs from the query
От | Tom Lane |
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Тема | Re: BUG #17150: Unexpected outputs from the query |
Дата | |
Msg-id | 1369911.1629226603@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: BUG #17150: Unexpected outputs from the query ("David G. Johnston" <david.g.johnston@gmail.com>) |
Ответы |
Re: BUG #17150: Unexpected outputs from the query
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Список | pgsql-bugs |
"David G. Johnston" <david.g.johnston@gmail.com> writes: > On Tuesday, August 17, 2021, PG Bug reporting form <noreply@postgresql.org> > wrote: >> This >> unexpected return can be fixed by removing "ORDER BY ( SELECT COUNT ( v1 ) >> )", then the query returns sum="0" as expected. > Well, PostgreSQL cannot remove the order by otherwise it would be a > different query. So your suggestion is spot on, and the user should > probably do that, but it doesn’t seem like a bug. Yeah. PG interprets SELECT x FROM v2 ORDER BY (SELECT COUNT(v1)) to behave the same as SELECT x, (SELECT COUNT(v1)) FROM v2 ORDER BY 2 (modulo the fact that the ORDER BY column won't be output), and then it turns out that that's effectively the same as SELECT x, COUNT(v1) FROM v2 ORDER BY 2 the reason being that since v1 is a variable of the outer query, the aggregate is considered to be an aggregate of the outer query *not* the sub-select. (That's required by the SQL standard.) So at this point you have an aggregated query that is certain to return 1 row, not more or less, regardless of how many rows are returned by v2. regards, tom lane
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