Re: Outer join query plans and performance
От | Tom Lane |
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Тема | Re: Outer join query plans and performance |
Дата | |
Msg-id | 13679.1130249522@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Outer join query plans and performance (Rich Doughty <rich@opusvl.com>) |
Ответы |
Re: Outer join query plans and performance
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Список | pgsql-performance |
Rich Doughty <rich@opusvl.com> writes: > EXPLAIN SELECT * > FROM > tokens.ta_tokens t LEFT JOIN > tokens.ta_tokenhist h1 ON t.token_id = h1.token_id LEFT JOIN > tokens.ta_tokenhist h2 ON t.token_id = h2.token_id > WHERE > h1.histdate = 'now'; > EXPLAIN SELECT * > FROM > tokens.ta_tokens t LEFT JOIN > tokens.ta_tokenhist h1 ON t.token_id = h1.token_id LEFT JOIN > tokens.ta_tokenhist h2 ON t.token_id = h2.token_id > WHERE > h2.histdate = 'now'; The reason these are different is that the second case constrains only the last-to-be-joined table, so the full cartesian product of t and h1 has to be formed. If this wasn't what you had in mind, you might be able to rearrange the order of the LEFT JOINs, but bear in mind that in general, changing outer-join ordering changes the results. (This is why the planner won't fix it for you.) regards, tom lane
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