Re: Update performance ... is 200,000 updates per hour what I should expect?
От | Tom Lane |
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Тема | Re: Update performance ... is 200,000 updates per hour what I should expect? |
Дата | |
Msg-id | 13345.1070382751@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Update performance ... is 200,000 updates per hour what I should expect? (Erik Norvelle <erik@norvelle.net>) |
Список | pgsql-performance |
Erik Norvelle <erik@norvelle.net> writes: > update indethom > set query_counter =3D nextval('s2.query_counter_seq'), -- Just= > =20=20 > for keeping track of how fast the query is running > sectref =3D (select clavis from s2.sectiones where > s2.sectiones.nomeoper =3D indethom.nomeoper > and s2.sectiones.refere1a =3D indethom.refere1a and=20=20 > s2.sectiones.refere1b =3D indethom.refere1b > and s2.sectiones.refere2a =3D indethom.refere2a and=20=20 > s2.sectiones.refere2b =3D indethom.refere2b > and s2.sectiones.refere3a =3D indethom.refere3a and=20=20 > s2.sectiones.refere3b =3D indethom.refere3b > and s2.sectiones.refere4a =3D indethom.refere4a and=20=20 > s2.sectiones.refere4b =3D indethom.refere4b); This is effectively forcing a nestloop-with-inner-indexscan join. You might be better off with update indethom set query_counter = nextval('s2.query_counter_seq'), sectref = sectiones.clavis from s2.sectiones where s2.sectiones.nomeoper = indethom.nomeoper and s2.sectiones.refere1a = indethom.refere1a and s2.sectiones.refere1b = indethom.refere1b and s2.sectiones.refere2a = indethom.refere2a and s2.sectiones.refere2b = indethom.refere2b and s2.sectiones.refere3a = indethom.refere3a and s2.sectiones.refere3b = indethom.refere3b and s2.sectiones.refere4a = indethom.refere4a and s2.sectiones.refere4b = indethom.refere4b; regards, tom lane
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