how to pass the function caller's parameter to inside the function. syntax error at or near "$1"
| От | leaf_yxj |
|---|---|
| Тема | how to pass the function caller's parameter to inside the function. syntax error at or near "$1" |
| Дата | |
| Msg-id | 1332951496887-5601045.post@n5.nabble.com обсуждение исходный текст |
| Ответы |
Re: how to pass the function caller's parameter to inside
the function. syntax error at or near "$1"
|
| Список | pgsql-general |
I want to create a function which use to truncate the table specified by the caller. I very confused how postgresql pass this parameter into the function : as a superuser to execute : 1) create or replace function d() returns void as $$ analyze; $$ language sql; ----- this works when i issue select d() 2) this doesn't work create or replace function v(text) returns void as $$ analyze $1; $$ language sql; why???? and how to correct it? I tried another function for insert 1) this works. create or replace function insert_f(integer) returns void as $$ insert into t1 values($1); $$ language sql; ----this works when i issue select insert_f(20); 2) this doesn't work. create or replace function insert_f(text,integer) returns void as $$ insert into $1 values($2); $$ language sql; ---- it failed to create the function and give me error : syntax error at or near "$1". Please help. Thanks. Regards. Grace -- View this message in context: http://postgresql.1045698.n5.nabble.com/how-to-pass-the-function-caller-s-parameter-to-inside-the-function-syntax-error-at-or-near-1-tp5601045p5601045.html Sent from the PostgreSQL - general mailing list archive at Nabble.com.
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