Re: Foreign table permissions and cloning
От | Peter Eisentraut |
---|---|
Тема | Re: Foreign table permissions and cloning |
Дата | |
Msg-id | 1303754973.5006.46.camel@vanquo.pezone.net обсуждение исходный текст |
Ответ на | Re: Foreign table permissions and cloning (Robert Haas <robertmhaas@gmail.com>) |
Список | pgsql-hackers |
On mån, 2011-04-25 at 13:35 -0400, Robert Haas wrote: > Hmm, it appears we had some pre-existing inconsistency here, because > ALL TABLES IN <schema> currently includes views. Which makes sense because you use GRANT ... ON TABLE to grant privileges to views. > That's weird, but > it'll be even more weird if we adopt the approach suggested by this > patch, which creates ALL FOREIGN TABLES IN <schema> but allows ALL > TABLES IN <schema> to go on including views. Maybe there is an > argument for having ALL {TABLES|VIEWS|FOREIGN TABLES} IN <schema> - or > maybe there isn't - but having two out of the three of them doesn't do > anything for me. For now I think we should go with the path of least > resistance and just document that ALL TABLES IN <schema> now includes > not only views but also foreign tables. Yes. > Putting that together with the comments already made upthread, the > only behavior changes I think we should make here are: > > - Add GRANT privilege [(column_list)] ON FOREIGN TABLE table TO role. > - Require that the argument to GRANT privilege [(column_list)] ON > TABLE TO role be an ordinary table, not a foreign table. But that would be contrary to the SQL standard. The current behavior is fine, AFAICT.
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