Re: Quoting $user as Parameter to SET
От | Tom Lane |
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Тема | Re: Quoting $user as Parameter to SET |
Дата | |
Msg-id | 12751.1121123080@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Quoting $user as Parameter to SET ("Thomas F. O'Connell" <tfo@sitening.com>) |
Ответы |
Re: Quoting $user as Parameter to SET
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Список | pgsql-general |
"Thomas F. O'Connell" <tfo@sitening.com> writes: > This is an important distinction because testing reveals that the > quoted $user after the reversal is no longer actually a dynamic > variable that results in a search_path that resolves to the current > user. Really? It works fine for me: regression=# create schema postgres; CREATE SCHEMA regression=# show search_path; search_path -------------- $user,public (1 row) regression=# select current_schemas(true); current_schemas ------------------------------ {pg_catalog,postgres,public} (1 row) regression=# alter database regression set search_path = public, '$user'; ALTER DATABASE regression=# \c - You are now connected to database "regression". regression=# show search_path; search_path ----------------- public, "$user" (1 row) regression=# select current_schemas(true); current_schemas ------------------------------ {pg_catalog,public,postgres} (1 row) regression=# regards, tom lane
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