Re: PostgreSQL Advocacy, Thoughts and Comments
От | Oliver Elphick |
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Тема | Re: PostgreSQL Advocacy, Thoughts and Comments |
Дата | |
Msg-id | 1070092424.7716.20.camel@linda.lfix.co.uk обсуждение исходный текст |
Ответ на | Re: PostgreSQL Advocacy, Thoughts and Comments ("cnliou" <cnliou@so-net.net.tw>) |
Ответы |
Re: PostgreSQL Advocacy, Thoughts and Comments
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Список | pgsql-general |
On Sat, 2003-11-29 at 04:37, cnliou wrote: > "Jason Tesser" <JTesser@nbbc.edu> > > > MySQL cannot even handle sub-queries yet. > > Ohh! Really? > Allow me to pay my highest respect to the genius mySQL > programmers! > I completely have no clue on how to construct any single > tiny database on a DBMS having no sub-query capability. > > Being too dumb, I solicit mySQL programmers' help by showing > me employee FOO's birthday and his/her latest job title > effective on or before 2003-1-1 from the following tables: > > CREATE TABLE t1 (employee TEXT,BirthDay DATE); > CREATE TABLE t2 (employee TEXT,EffectiveDate DATE,JobTitle > TEXT); > > And make the result like this: > > FOO 1980-1-1 programmer > > Please do not give me the answer that you will merge these > two tables to form one like this: > > CREATE TABLE t1 (employee TEXT,BirthDay DATE,EffectiveDate > DATE,JobTitle TEXT); I have great trouble following your meaning, but I think you are talking about joining two tables in a query: SELECT t1.employee, t1.birthday, t2.jobtitle FROM t1, t2 WHERE t1.employee = t2.employee; That is not the same as using a sub-query: SELECT employee FROM t1 WHERE birthday > ( SELECT MIN(effectivedate) FROM t2 ); (select employees who were born after the longest-serving employee started work.) -- Oliver Elphick Oliver.Elphick@lfix.co.uk Isle of Wight, UK http://www.lfix.co.uk/oliver GPG: 1024D/3E1D0C1C: CA12 09E0 E8D5 8870 5839 932A 614D 4C34 3E1D 0C1C ======================================== "Who shall ascend into the hill of the LORD? or who shall stand in his holy place? He that hath clean hands, and a pure heart..." Psalms 24:3,4
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