RE: Select Distinct Order By Array_Position
| От | Mark Williams |
|---|---|
| Тема | RE: Select Distinct Order By Array_Position |
| Дата | |
| Msg-id | 004e01d485c2$6c45cb50$44d161f0$@gmail.com обсуждение исходный текст |
| Ответ на | Re: Select Distinct Order By Array_Position (Rob Sargent <robjsargent@gmail.com>) |
| Ответы |
Re: Select Distinct Order By Array_Position
|
| Список | pgsql-sql |
Wasn’t aware it was possible to put array_position statement in the actual select or is this a select within a select?
Also, I am selecting from an ordered (randomly) subset of data and I need to return the result set in the same order so do have to output the array as part of the order by?
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From: Rob Sargent <robjsargent@gmail.com>
Sent: 26 November 2018 19:20
To: Mark Williams <markwillimas@gmail.com>
Cc: pgsql-sql@lists.postgresql.org
Subject: Re: Select Distinct Order By Array_Position
On Nov 26, 2018, at 12:12 PM, Mark Williams <markwillimas@gmail.com> wrote:
Hi,
I am getting an error “SELECT DISTINCT, ORDER BY expressions must appear in select list”. I am ordering by documents.id and it appears in my select list. So I am guessing the problem lies with the array. Is there any way of achieving this? Query is below.
SELECT DISTINCT documents.id, page_no FROM texts LEFT JOIN documents on documents.id=texts.doc_id WHERE doc_id IN (26194, 2345, 189) AND (text LIKE '%RIVER%') ORDER BY array_position(ARRAY[26194, 2345, 189]::INTEGER[], documents.id)
Thanks,
Mark
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Try put the array_position clause in the select and add documents.id to the order by?
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