Re: list of index
От | FarjadFarid\(ChkNet\) |
---|---|
Тема | Re: list of index |
Дата | |
Msg-id | 002e01cfb899$aba86280$02f92780$@checknetworks.com обсуждение исходный текст |
Ответ на | list of index ("FarjadFarid\(ChkNet\)" <farjad.farid@checknetworks.com>) |
Список | pgsql-general |
Thanks Melvin, That worked for me. Great.
From: Melvin Davidson [mailto:melvin6925@yahoo.com]
Sent: 15 August 2014 15:46
To: farjad.farid@checknetworks.com; pgsql-general@postgresql.org
Subject: Re: [GENERAL] list of index
>On a Postgresql database i like to obtain (using an sql
>statement) the list of all user defined indexes and their
>details specially the column "order by" sort order. e.g.
>ASC or DESC. Any help would be much appreciated.
either of the following queries should help:
SELECT pg_get_indexdef(idx.indexrelid) || ';'
FROM pg_stat_all_indexes i
JOIN pg_class c ON (c.oid = i.relid)
JOIN pg_namespace n ON (n.oid = c.relnamespace)
JOIN pg_index idx ON (idx.indexrelid = i.indexrelid )
WHERE NOT idx.indisprimary
AND NOT idx.indisunique
AND i.relname NOT LIKE 'pg_%'
AND i.idx_scan = 0
ORDER BY n.nspname,
i.relname;
SELECT n.nspname as schema,
i.relname as table,
i.indexrelname as index,
i.idx_scan,
i.idx_tup_read,
i.idx_tup_fetch,
pg_size_pretty(pg_relation_size(quote_ident(n.nspname) || '.' || quote_ident(i.relname))) AS table_size,
pg_size_pretty(pg_relation_size(quote_ident(n.nspname) || '.' || quote_ident(i.indexrelname))) AS index_size,
pg_get_indexdef(idx.indexrelid) as idx_definition
FROM pg_stat_all_indexes i
JOIN pg_class c ON (c.oid = i.relid)
JOIN pg_namespace n ON (n.oid = c.relnamespace)
JOIN pg_index idx ON (idx.indexrelid = i.indexrelid )
WHERE n.nspname NOT LIKE 'pg_%'
ORDER BY 1, 2, 3;
Melvin Davidson
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