Re: BUG #2107: Function INOUT parameter not returned to caller,

Tom Lane wrote:
> "Tony S"  writes:
> 
>>Function defined with INOUT parameter.  Value of parameter is not returned
>>to calling function.
> 
> 
> You are confused about the meaning and use of INOUT.  It's not some kind
> of pass-by-reference parameter, it's just a shorthand for separate IN
> and OUT parameters.  In your example, the PERFORM discards the function
> result; the original value of 'outparameter' is not and cannot be
> modified by the called function.
> 
> 			regards, tom lane


This is very much my mistake.  I had indeed taken them to be a sort of
pass-by-reference parameter, and not part of the result definition,
which they actually are.  Running PERFORM is pointless, then, too.