You may use something like this in a stored function:
DECLARE
a INTEGER[];
BEGIN
a := '{2341548, 2325251, 2333130, 2015421,2073536, 2252374, 2273219, 2350850, 2367318, 2032977, 2032849}';
select * from users where id = any(a) order by idx(a, id);
END;
Or in the plain SQL:
select * from users where id = any(a) order by idx('{2341548, 2325251, 2333130, 2015421,2073536, 2252374, 2273219, 2350850, 2367318, 2032977, 2032849}', id);
Note that it is pretty fast only if the array contains not too much elements (e.g. 20). Do not use for large arrays!
On Sun, Aug 17, 2008 at 4:11 AM, mark
<markkicks@gmail.com> wrote:
hi
if i execute this statement:
select * from users where id in (2341548, 2325251, 2333130, 2015421,
2073536, 2252374, 2273219, 2350850, 2367318, 2032977, 2032849, )
the order of rows obtained is random.
is there anyway i can get the rows in the same order as the ids in
subquery? or is there a different statement i can use?
thanks!
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