-----Original Message-----
From: Igor Neyman
Sent: Thursday, September 22, 2016 10:33 AM
To: 'Sven R. Kunze' <srkunze@mail.de>; pgsql-performance@postgresql.org
Subject: RE: [PERFORM] Multiple-Table-Spanning Joins with ORs in WHERE Clause
-----Original Message-----
From: pgsql-performance-owner@postgresql.org [mailto:pgsql-performance-owner@postgresql.org] On Behalf Of Sven R.
Kunze
Sent: Thursday, September 22, 2016 9:25 AM
To: pgsql-performance@postgresql.org
Subject: [PERFORM] Multiple-Table-Spanning Joins with ORs in WHERE Clause
Hi pgsql-performance list,
what is the recommended way of doing **multiple-table-spanning joins with ORs in the WHERE-clause**?
Until now, we've used the LEFT OUTER JOIN to filter big_table like so:
SELECT DISTINCT <fields of big_table>
FROM
"big_table"
LEFT OUTER JOIN "table_a" ON ("big_table"."id" =
"table_a"."big_table_id")
LEFT OUTER JOIN "table_b" ON ("big_table"."id" =
"table_b"."big_table_id")
WHERE
"table_a"."item_id" IN (<handful of items>)
OR
"table_b"."item_id" IN (<handful of items>);
However, this results in an awful slow plan (requiring to scan the complete big_table which obviously isn't optimal).
So, we decided (at least for now) to split up the query into two separate ones and merge/de-duplicate the result with
applicationlogic:
SELECT <fields of big_table>
FROM
"big_table" INNER JOIN "table_a" ON ("big_table"."id" =
"table_a"."big_table_id")
WHERE
"table_a"."item_id" IN (<handful of items>);
SELECT <fields of big_table>
FROM
"big_table" INNER JOIN "table_b" ON ("big_table"."id" =
"table_b"."big_table_id")
WHERE
"table_b"."item_id" IN (<handful of items>);
As you can imagine we would be very glad to solve this issue with a
single query and without having to re-code existing logic of PostgreSQL.
But how?
Best,
Sven
PS: if you require EXPLAIN ANALYZE, I can post them as well.
______________________________________________________________________________________________
Another option to try::
SELECT DISTINCT <fields of big_table>
FROM
"big_table"
LEFT OUTER JOIN "table_a" ON ("big_table"."id" = "table_a"."big_table_id" AND "table_a"."item_id" IN (<handful of
items>))
LEFT OUTER JOIN "table_b" ON ("big_table"."id" = "table_b"."big_table_id" AND "table_b"."item_id" IN (<handful of
items>));
Regards,
Igor Neyman