On Sun, Aug 25, 2013 at 5:59 PM, Janek Sendrowski <janek12@web.de> wrote:
SELECT v_rec1.user, sum(CASE WHEN v_rec_fts.lev BETWEEN 0 AND 25 THEN 1 ELSE 0 END) as "0 to 25", sum(CASE WHEN v_rec_fts.lev BETWEEN 25 AND 50 THEN 1 ELSE 0 END) as "25 to 50", sum(CASE WHEN v_rec_fts.lev BETWEEN 50 AND 100 THEN 1 ELSE 0 END) as "50 to 100" INTO v_rec2 GROUP BY user;
Now I want to summuarize the "0 to 25" values and the others in the same query. Somehow like this: count("0 to 25") But I want to do it with every single user and I don't know how to do that
A result should look like this:
user percentage count smith "0 to 25" 5 smith "25 to 50" 7 smith "50 to 75" 2 jones "0 to 25" 11 jones "25 to 50" 1 jones "50 to 75" 3
This appears to be some kind of equal interval problem.
SELECT v_rec1.user,
WIDTH_BUCKET(v_rec_fts.lev, 0, 100, 4) AS bucket
COUNT(*) as count, FROM v_rec2 GROUP BY user, bucket;
(Untested, but this should be the gist.)
Bucket 1 would be 0 to 25, bucket 2 is 25 to 50, 3 is 50 to 75, 4 is 75 to 100. If you really need to change the bucket number to some kind of text, you can probably nest this query inside another that uses a CASE to pick the text based on on the bucket number.